Tentukan persamaan garis yang tegak lurus 2y+-7/4(x-7)dan melalui titik (-2,-3)

2y - 7/4 (x - 7) = 0
2y - 7/4 x + 49/7 = 0
2y = 7/4 x + 49/7
y = 7/8 x + 49/14
m = 7/8

syarat tegak lurus
m1 . m2 = - 1
7/8 . m2 = - 1
m2 = - 1 ÷ 7/8
m2 = - 8/7

pers garis
y - y1 = m (x - X1)
y + 3 = - 8/7 (x + 2)
y = - 8/7 x - 16/7 - 3
y = - 8/7 x - 37/7
------------------------(×7)
7y = - 8x - 37