tolong bantu ya tentukan persamaan garis yg melalui titik (2,2) dan (-6,10) pakai cara

(y-y1)/(y2-y1)=(x-x1)/(x2-x1)
<=> (y-2)/(10-2)=(x-2)/(-6-2)
<=> (y-2)/(8)=(x-2)/(-8)
<=> -8(y-2)=8(x-2)
<=> -8y+16=8x-16
<=> -8y=8x-16-16
<=> -8y=8x-32
<=> y=(8x-32)/(-8)
<=> y= -x+4