Diketahui fungsi f:R–>R dengan rumus f(x)=x²-4x+5,x € R .Tentukan f(0),f(4),f(6),dan f(-1) ! Tolong jawabnya yg bner, Mkasii

f(x)=x²-4x+5
f(0) = 0²-4(0)+5 = 5
f(4) = 4²-4(4)+5 = 16-16+5 = 5
f(6) = 6²-4(6)+5 = 36-24+5 = 17
f(-1) = (-1)²-4(-1)+5 = 1+4+5 = 10

semoga membantu yaa:)

f(x) = x^2 - 4x + 5

f(0) = 0^2 - 4(0) + 5
f(0) = 5

f(4) = 4^2 - 4(4) + 5
f(4) = 16 - 16 + 5
f(4) = 5

f(6) = 6^2 - 4(6) + 5
f(6) = 36 - 24 + 5
f(6) = 17

f(-1) = -1^2 - 4(-1) + 5
f(-1) = 1 + 4 + 5
f(-1) = 10

jadi f(0) = 5, f(4) = 5, f(6) = 17, dan f(-1) = 10