Tentukan persamaan garis yang melaleuca titik (12,-8)dan sejajar dengan garis 7x-3y-8=0

Bab Persamaan Garis
Matematika SMP Kelas VIII

ax + by + c = 0, sejajar, (p, q)
ax + by - (ap + bq) = 0

7x - 3y - 8 = 0, sejajar, (12, -8)
7x - 3y - (7 . 12 - 3 . (-8)) = 0
7x - 3y - (84 + 24) = 0
7x - 3y - 108 = 0

7x - 3y - 8 = 0
3y = 7x - 8
y = 7/3 x - 8/3
m = 7/3

y - y₁ = m (x - x₁)
y - (-8) = 7/3 (x - 12)
3 (y + 8) = 7 (x - 12) 
3y + 24 = 7x - 84
7x - 3y - 108 = 0