Matematika

Pertanyaan

mohon bantuannya no 17
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mohon bantuannya no 17 jika bisa ads keterangan

1 Jawaban

  • x - 3y + 2 = 0
    - 3y = - x - 2
    y = ⅓ x + ⅔
    m= ⅓

    syarat sejajar m1 = m2 = ⅓

    pers garis
    y - y1 = m (x - x1)
    y - 5 = ⅓(x + 2)
    y = ⅓ x + 2/3 + 5
    y = ⅓ x + 17/3
    -----------------------(×3)
    3y = x + 17
    3y - x = 17
    x - 3y = - 17 (C)