tolong bantu cari hp nya

Bab Sistem Persamaan Linear Kuadrat Dua Variabel

y = x^2
x^2 + y^2 = 1

x^2 + y^2 = 1
y + y^2 = 1
y^2 + y - 1 = 0

Cek diskriminan
a = 1, b = 1, c = -1
D = (1)^2 - 4(1)(-1)
D = 1 + 4
D = 5
Berarti persamaan memiliki 2 penyelesaian

y1,2 = (-(1) +- √(1^2 - 4(1)(-1)))/2(1)
y1,2 = (-1 +- √5)/2

y1 = (-1 + √5)/2 ; y2 = (-1 - √5)/2

y = x^2
x = √y

x1 = √y1
x1 = √((-1 + √5)/2)

x2 = √y2
x2 = √((-1 - √5)/2)

HP = {((-1 + √5)/2, √((-1 + √5)/2)) ; ((-1 - √5)/2 , √((-1 - √5)/2))}