rumus fungsi f(x)= ax + b .jika f(-4) =13 dan f(3) = -1 . maka nilai f(-2) adalah

f(x) = ax + b

f(-4) = -4a + b = 13
f(3) = 3a + b = -1

-4a + b = 13
3a + b = -1
_________ -
-7a = 14
a = -2

a = -2 disubtitusi ke
3a + b = -1
3.(-2) + b = -1
-6 + b = -1
b = -1 + 6
b = 5

f(-2) = -2a + b = -2.(-2) + 5
= 4 + 5
= 9

jadi, f(-2) hasilnya 9