nilai minimum fungsi kkuadrat f(x)=3×^2-24×+7 adalah

f(x) = 3x² - 24x + 7

a = 3
b = -24
c = 7


Nilai min.
[tex] \frac{D}{-4a} \\ = \frac{(-24)^2-4(3)(7)}{-4(3)} \\ = \frac{576-84}{-12} \\ = \frac{492}{-12} \\ = -41 [/tex]