hasil dari 4log(2X2-4X+16) = 2log(X+2)

[tex] {}^{4} log( {2x}^{2} - 4x + 16 ) = {}^{2} log(x + 2) \\ \frac{1}{2} {}^{2} log( {2x}^{2} - 4x + 16 )= {}^{2} log(x + 2) \\ {2x}^{2} - 4x + 16 = 2(x + 2) \\ {2x}^{2} - 4x + 16 = 2x + 4 \\ {2x}^{2} - 6x + 12 = 0 \\ [/tex]
nanti tinggal difaktorkan

semoga membantu