tlong bantuannya. bsok d kumpulkan. 2/x+1 + 2/y-3 + 3/z+1 =2 -4/x+1 + 1/y-3 + 6/z+2=5 4/x+1 + 3/y-3 + 3/z+2=2 carilah hasil penyelesaian persamaan 3 variabel te

misalkan
1/x+2 = a
1/y-3 = b
1/z+1 = c

maka sistem persamaanya menjadi:
2a + 2b + 3c = 2
-4a + b + 6c = 5
4a + 3b + 3c = 2

eliminasi c
2a + 2b + 3c = 2 (×2) 4a + 4b + 6c = 4
-4a + b + 6c = 5 (×1) -4a + b + 6c = 5
_____________ -
8a + 3b = -1

2a + 2b + 3c = 2
4a + 3b + 3c = 2
_____________ -
-2a - b = 0
-2a = b

8a + 3b = -1
8a -6a = -1
a = - 1/2

b = 1

2a + 2b + 3c = 2

-1 + 2 +3c =2
c = 1/3

a =-1/2
maka
x+1= -2
x = -3

b = 1
maka
y-3 = 1
y = 4

c = 1/3
maka
z+2 = 3
z = 1