Carilah nilai x,y,dan z 5y-8z=-19 5x-8z=6 3x-2y=12 (Sistem persamaan linear tiga variabel)

5y-8z=-19 ...(1)
5x-8z=6 ....(2)
3x-2y=12 ...(3)

Substitusi
5x-8z=6
z=(5x-6)/8 ...(4)

Masukan ke pers (1)
5y-(8((5x-6)/8))=-19
5y-(5x-6)=-19
5y-5x=-13 ....(5)

Eliminasi (3)&(5)
3x-2y=12 |×5| 15x-10y=60
5x-5y=-13 |×2| 10x-10y=-26
------------------ -
5x=86
x=17.2

Subtitusi x=17.2 ke pers, (3)
3x-2y=12
3(17.2)-12=2y
Y=39.6/2
Y=-19.8

Subtitusi ke pers. (2)
5(17.2)-8z=6
86-6=8z
Z=-10



Diliat lagi...maaf kalo salah