(2.logx-1)1/^xlog10=log10 Maka x1.x2=....
Matematika
Mfadil31
Pertanyaan
(2.logx-1)1/^xlog10=log10
Maka x1.x2=....
Maka x1.x2=....
1 Jawaban
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1. Jawaban kaksyaif
(2.logx-1). 1/xlog10 = log10
(2.logx - 1). logx = 1
misalkan
logx = a
(2a-1).a = 1
2a^2 -a = 1
2a^2 - a - 1 = 0
cara 1
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(2a + 1)(a- 1) = 0
a = -1/2 atau a = 1
a = -1/2
logx = -1/2
x = 10^(-1/2) = 1/akar10
a = 1
logx = 1
x = 10^1 = 10
maka x1.x2 = 10^(-1/2) . 10 = 10^1/2 = akar10
cara 2
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2a^2 - a - 1 = 0
a1+a2 = 1/2
logx1 + logx2 = 1/2
logx1.x2 = 1/2
x1.x2 = 10^(1/2) = akar10