Matematika

Pertanyaan

(2.logx-1)1/^xlog10=log10

Maka x1.x2=....

1 Jawaban

  • (2.logx-1). 1/xlog10 = log10
    (2.logx - 1). logx = 1
    misalkan
    logx = a
    (2a-1).a = 1
    2a^2 -a = 1
    2a^2 - a - 1 = 0

    cara 1
    ----------

    (2a + 1)(a- 1) = 0
    a = -1/2 atau a = 1

    a = -1/2
    logx = -1/2
    x = 10^(-1/2) = 1/akar10

    a = 1
    logx = 1
    x = 10^1 = 10

    maka x1.x2 = 10^(-1/2) . 10 = 10^1/2 = akar10

    cara 2
    ---------

    2a^2 - a - 1 = 0

    a1+a2 = 1/2
    logx1 + logx2 = 1/2
    logx1.x2 = 1/2
    x1.x2 = 10^(1/2) = akar10


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