Persamaan garis lurus
Matematika
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Pertanyaan
Persamaan garis lurus
1 Jawaban
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1. Jawaban cupid85
10) m = (y2 - y1) / (x2 - X1)
m = (4 - 2) / (3 - 1)
m = 2 / 2
m = 1 (A)
11) (y - y1) / (y2 - y1) = (x - X1) / (x2 - X1)
(y - 2) / (4 - 2) = (x - 1) / (3 - 1)
(y - 2) / 2 = (x - 1) / 2
2(y - 2) = 2 (x - 1)
2y - 4 = 2x - 2
2y = 2x - 2 + 4
2y = 2x + 2
y = x + 1 (D)
12) 2y + 2x = 3
2y = - 2x + 3
y = - 1 + 3/2
m1 = - 1
syarat sejajar m1 = m2 = - 1
y - y1 = m (x - X1)
y - 6 = - 1 (x - 3)
y = - x + 3 + 6
y = - x + 9 (A)
13) 4y - 3x = 5
4y = 3x + 5
m = ¾
syarat sejajar m1 = m2 = ¾
y - y1 = m (x - X1)
y - 6 = ¾ (x + 3)
y = ¾ x + 9/4 + 6
y = ¾ x + 33/4
------------------------(×4)
4y = 3x + 33 (D)