Matematika

Pertanyaan

120°C=.....°F=.....°R=.....K

1 Jawaban

  • 120°C
    Tf = 5/9 Tc + 32
        = 5/9 × 120 + 32
        = 5/9 × 152
        = 84,4°F

    Tr = 4/5 Tc
        = 4/5 120
        = 96°R

    Tk = Tc + 273
         = 120 + 273
         = 393°K

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