Di ketahui f (x)=ax+b jika f (3)=7dan f(-2)=2 maka nilai a+b adalah

f(3)= 7
f(-2)= 2
f(3)= 3a + b = 7 |x2 | 6a + 2b = 14
f(-2)= -2a + b = 2|x3 | -6a + 3b = 6
+
5b = 20
b = 4
3a + b = 7
3a + 4 = 7
3a = 7 - 4
3a = 3
a = 1
Jadi a+ b =
4 + 1 = 5