f(x)=2x-3 ; g(x)=x^+2x-3 tentukan rumus fungsi komposisi a. (g0f)(x) b. (f0f0g)(x)

f(x)=2x-3 ; g(x)=x^+2x-3
a. (g0f)(x)
= (2x-3)^2+2(2x-3)-3
= (4x^2 -12x +9) + 4x-6 -3
= 4x^2 - 8x
= 4x (x-2)
b. (f0f0g)(x)
= 2(2(x^2+2x-3)-3)-3
= 2(2x^2 +4x-6-3)-3
= 4x^2 + 8x - 18 - 3
= 4x^2 + 8x -21

Maaf lama, ngetiknya pakai hp.

(gof)(x)=g(f(x))
= g(2x-3)
= (2x-3)²+2(2x-3)-3
=4x²-12x+9+4x-6-3
=4x²-8x

(fog)(x)= f(gx)
=f(x²+2x-3)
=2(x²+2x-3)-3
=2x²+4x-9
(fofog)(x)= f (fog(x))
=f(2x²+4x-9)
=2( 2x²+4x-9)-3
=4x²+8x-21