larutan ilodium sebanyak 20ml dam air 200ml berapakah kadar larutan tersebut?

Kita asumsikan ρ = 1 gram/mL.
maka massa air limbah = ρ x v = 1 x 200 = 200 gram.
massa kadmium = 2 mg = 0,002 gram

bpj = (massa kadmium / massa air limbah) x 10⁶
bpj = (0,002 / 200) x 10⁶
bpj = 10

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