Matematika

Pertanyaan

tan 37,5derajat+tan82,5derajat

1 Jawaban

  • Trigonometri.

    tan A + tan B = sin A / cos A + sin B / cos B
    = (sin A cos B + cos A sin B) / (cos A cos B)
    = 2 sin (A + B) / [cos (A + B) + cos (A - B)]
    Dan ingat, cos (-θ) = cos θ

    tan 37,5° + tan 82,5°
    = 2 sin (37,5° + 82,5°) / [cos (37,5° + 82,5°) + cos (37,5° - 82,5°)]
    = 2 sin 120° / (cos 120° + cos 45°)
    = 2 (1/2 √3) / (-1/2 + 1/2 √2)
    = √3 / (√2 - 1) / 2
    = 2√3 / (√2 - 1) [(√2 + 1) / (√2 + 1)]
    = 2(√6 + √3)

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