no 3 please. beserta caranya ya

[tex](x + 2)(x - 5) - (5 \times - x) = - 7\\ x^{2} - 3x - 10 + 5x = - 7 \\ {x}^{2} + 2x - 10 = - 7 \\ {x}^{2} + 2x - 3 = 0 \\ (x + 3)(x - 1) \\ x = - 3 \: atau \: x = 1[/tex]

Berlaku ad-bc = -7

| A | = ad - bc. | A | = -7
(x+2)(x-5) - (-x .5) = -7
x^2 - 3x - 10 -(-5x) = -7
x^2 -3x -10+5x +7 = 0
x^2 +2x -3 = 0
(x + 3)(x - 1) = 0
x = -3 atau x = 1