y² = x - 1 (x - 3)² + y² = 4 selesaikan persamaan diatas! mohon bantuannya

Y² = x-1
-x = -1 - y²
x = 1+y²

y^2 = x - 1, subsitusikan ke (x - 3)^2 + y^2 = 4
maka (x - 3)^2+(x-1)= 4
x^2 -6x +9 + x -1 = 4
x^2 -5x +4 = 0
(x-1)(x-4) = 0
x1 = 1 atau x2 = 4
(y1)^2 = 1-1
(y1)^2 = 0
y1 = 0
(y2)^2 = 4-1
(y2)^2 = 3
y2 = +.-√3
HP = { ( 1,0),(4,√3),(4,-√3) }