pd suatu barisan geometri diket U1=135 dan U3=15.berapa nilai suku ke-5
Matematika
susanineke
Pertanyaan
pd suatu barisan geometri diket U1=135 dan U3=15.berapa nilai suku ke-5
2 Jawaban
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1. Jawaban cupid85
U1 = a = 135
U3 = ar²
15 = 135 . r²
r² = 15 / 135
r² = 1/9
r = ⅓
U5 = ar⁴
= 135 . (⅓)⁴
= 135 . 1/81
= 135/81
= 1 54/81
= 1 ⅔ -
2. Jawaban Vio0507
U1 = a = 135
U3 = ar² = 15 = 135r²
r² = 15 / 135 = 1/9
r = 1/3
U5 = ar^4 =135(1/3)^4=135/81