cara soal berikut tolong bantuannya , tolong sekali ,, jawaban yg betul dan caranya

1. L.Lingkaran = π × r²
= 22/7 × 7²
= 22/7 × 49
= 159 cm²

2.L.Lingkaran = π × r²
= 22/7 × 17.5²
= 22/7 × 306.25
= 962.5 cm²

3.L. Lingkaran = ¼ × π × r²
= ¼ × 22/7 × 7²
= ¼ × 22/7 × 49
= ¼ × 159
= 39.75 cm

Maaf cuma sampai no 3 .
saya keburu mau pergi
semoga membantu :)
nanti saya ralat

1. L.Lingkaran = π × r²
= 22/7 × 7²
= 22/7 × 49
= 159 cm²

2. L.Lingkaran = π × r²
= 22/7 × 17.5²
= 22/7 × 306.25
= 962.5 cm²

3. L.Lingkaran = ¼ × π × r²
= ¼ × 22/7 × 7²
= ¼ × 22/7 × 49
= ¼ × 159
= 39.75 cm²

4. L.Lingkaran 1 = ½ × π × r²
= ½ × 22/7 × 3.5²
= ½ × 22/7 × 12.25
= ½ × 38.5
= 19.25 cm²
L.Lingkaran 2 = ½ × π × r²
= ½ × 22/7 × 3.5²
= ½ × 22/7 × 12.25
= ½ × 38.5 cm²
= 19.25 cm²
L.Lingkaran 3 = ½ × π × r²
= ½ × 22/7 × 7²
= ½ × 22/7 × 49
= ½ × 159
= 79.5 cm²
Total Luas Gabungan = 19.25 + 19.25 + 79.5 = 118 cm²

5. L.Lingkaran = ¾ × π × r²
= ¾ × 22/7 × 14²
= ¾ × 22/7 × 196
= ¾ × 616
= 462 cm²

Semoga Membantu :) Dikoreksi lgi
Udh ada rumusnya
``»•^°Mystic°^•«``