Persamaan garis yang melalui titik(-7,2) dan (5,4)adalah? Caranya?

y-y1/y2-y1 = x-x1/x2-x1
y-2/4-2 = x-(-7)/5-(-7)
y-2/2 = x+7/12
12(y-2) = 2(x+7)
12y-24 = 2x+14
12y - 2x - 38 = 0
6y - x - 19 = 0

Mapel       : Matematika
Kategori   : Persamaan Garis Lurus
Kelas        : SMP / MTs
Semester : Ganjil


Pembahasan:
[tex] \frac{y- y_{1}}{y_{2}-y_{1}} = \frac{x-x_{1}}{x_{2}-x_{1}} [/tex]
[tex] \frac{y- 2}{4-2} = \frac{x-(-7)}{5-(-7)} [/tex]
[tex] \frac{y- 2}{4-2} = \frac{x+7}{5+7} [/tex]
[tex]\frac{y- 2}{2} = \frac{x+7}{12}[/tex]
[tex]12(y-2) = 2(x+7)[/tex]
[tex]12y-24 = 2x+14[/tex]
[tex]12y - 2x - 38 = 0 (:2)[/tex]
[tex]6y - x - 19 = 0[/tex]