tolong bantu kerjain :'')
Matematika
jarazhr
Pertanyaan
tolong bantu kerjain :'')
2 Jawaban
-
1. Jawaban kembangapi
No. 1 skip dulu hehe
Coba dicek lagi, semoga membantu.2. Jawaban arsetpopeye
1) Lim (x√x - 2√x - 2√2 + x√2)/(√x - √2)
x=>2
Lim (x√x - 2√x + x√2 - 2√2)/(√x - √2)
x=>2
Lim (√x (x - 2) + √2 (x - 2)) / (√x - √2)
x=>2
Lim (x - 2)(√x + √2)/(√x - √2) . (√x + √2)/(√x + √2)
x=>2
Lim (x - 2)(√x + √2)(√x + √2) / (x - 2)
x=>2
Lim (√x + √2)(√x + √2)
x=>2
= (√2 + √2)(√2 + √2)
= (2√2)(2√2)
= 8
2) Lim (9 - x²)/[4 - √(x² + 7)]
x=>3
Lim (9 - x²)/[4 - √(x² + 7)] . [4 + √(x² + 7)]/[4 + √(x² + 7)]
x=>3
Lim (9 - x²)[4 + √(x² + 7)] / [16 - (x² + 7)]
x=>3
Lim (9 - x²)[4 + √(x² + 7)] / (9 - x²)
x=>3
Lim [4 + √(x² + 7)]
x=>3
= 4 + √(3² + 7)
= 4 + √16
= 8
3) Lim (4 - x²)/[3 - √(x² + 9)]
x=>2
Lim (4 - x²)/[3 - √(x² + 9)] . [3 + √(x² + 9)]/[3 + √(x² + 9)]
x=>2
Lim (4 - x²)[3 + √(x² + 5)] / (9 - (x² + 5))
x=>2
Lim (4 - x²)[3 + √(x² + 5)] / (4 - x²)
x=>2
Lim [3 + √(x² + 5)]
x=>2
= (3 + √(2² + 5))
= 3 + √9
= 6