Matematika

Pertanyaan

tolong bantu kerjain :'')
tolong bantu kerjain :'')

2 Jawaban

  • No. 1 skip dulu hehe
    Coba dicek lagi, semoga membantu.
    Gambar lampiran jawaban kembangapi
  • 1) Lim (x√x - 2√x - 2√2 + x√2)/(√x - √2)
    x=>2

    Lim (x√x - 2√x + x√2 - 2√2)/(√x - √2)
    x=>2

    Lim (√x (x - 2) + √2 (x - 2)) / (√x - √2)
    x=>2

    Lim (x - 2)(√x + √2)/(√x - √2) . (√x + √2)/(√x + √2)
    x=>2

    Lim (x - 2)(√x + √2)(√x + √2) / (x - 2)
    x=>2

    Lim (√x + √2)(√x + √2)
    x=>2

    = (√2 + √2)(√2 + √2)

    = (2√2)(2√2)

    = 8


    2) Lim (9 - x²)/[4 - √(x² + 7)]
    x=>3

    Lim (9 - x²)/[4 - √(x² + 7)] . [4 + √(x² + 7)]/[4 + √(x² + 7)]
    x=>3

    Lim (9 - x²)[4 + √(x² + 7)] / [16 - (x² + 7)]
    x=>3

    Lim (9 - x²)[4 + √(x² + 7)] / (9 - x²)
    x=>3

    Lim [4 + √(x² + 7)]
    x=>3

    = 4 + √(3² + 7)

    = 4 + √16

    = 8


    3) Lim (4 - x²)/[3 - √(x² + 9)]
    x=>2

    Lim (4 - x²)/[3 - √(x² + 9)] . [3 + √(x² + 9)]/[3 + √(x² + 9)]
    x=>2

    Lim (4 - x²)[3 + √(x² + 5)] / (9 - (x² + 5))
    x=>2

    Lim (4 - x²)[3 + √(x² + 5)] / (4 - x²)
    x=>2

    Lim [3 + √(x² + 5)]
    x=>2

    = (3 + √(2² + 5))

    = 3 + √9

    = 6