Matematika

Pertanyaan

fpb dari 40 ,16,10,25,12,42,20tolong

1 Jawaban

  • 40=2^20 = 2^10 = 2^5 =2³ x 5
    16 = 2^8 = 2^4 = 2^2 = 24
    10 = 2^5 = 2 x 5
    25 = 5^5 = 5²
    12 = 2^6 = 2^3 = 2² x 3
    42 = 2^21 = 3^7 = 2 x 3 x 7
    20 = 2^10 = 2^5 =2² x 5
    fpb = 2

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