2H2(g) + O2(g)⇒2H2O(I) ΔH = -571 kj 2Ca(s) + O2(g)⇒2CaO(s) ΔH = -1269 kj CaO(s) + H2O(I)⇒Ca(OH)2(s) ΔH = -64 kj
Kimia
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Pertanyaan
2H2(g) + O2(g)⇒2H2O(I) ΔH = -571 kj
2Ca(s) + O2(g)⇒2CaO(s) ΔH = -1269 kj
CaO(s) + H2O(I)⇒Ca(OH)2(s) ΔH = -64 kj
2Ca(s) + O2(g)⇒2CaO(s) ΔH = -1269 kj
CaO(s) + H2O(I)⇒Ca(OH)2(s) ΔH = -64 kj
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