Proyeksi vektor ortogonal v = ( 1 3 3) pada u=( 4 2 2 ) adalah

★ Vektor ★

IuI = √4²+2²+2²
= √16+4+4
= √24 = 2√6
z = v* u/ IuI ( u/ IuI)
= 1(4)+3(2)+3(2) / (√24) [ ( 4,2,2)/ √24]
= 4+12 / 24 ( 4,2,2)
= 16/24 ( 4,2,2 )
= 2/3 (4,2,2)
= ( 8/3,4/3,4/3 ) ← jawaban