diketahui suku banyak f(x).jika dibagi x^2-3x+2 sisanya4x+1,jika dibagi x^2-2x-15bersisa3x-2. jika dibagi oleh x^2+3x-3 hasilnya.....

jawab
("soal diubah , semula  dibagi  x^2 + 3x -3 , menjadi x^2 + 2x - 3 ")

s(x) = 4x + 1
x²- 3x +2 =(x -2)(x -1)
x= 2 → s(2) = 4(2) +1 =9
x = 1 → s(1) = 4(1) + 1 = 5

s(x) = 3x- 2
x² -2x -15 = (x -5)(x +3)
x = 5  → s(5) = 3(5)- 2 = 13
x = -3 → s(-3) = 3(-3) - 2 = -11

dibagi x² + 2x - 3 =(x +3)(x-1) , sisa s(x) = ax + b
s(-3) = -11 → -3a + b = - 11  (i)
s(1) = 5 → a + b = 5  (ii)

-3a + b = -11
a + b = 5  ||(-)
-4a = - 16
a = 4

a + b = 5
b = 5- a
b = 1

s(x) = ax + b
s(x) = 4x + 1