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Pertanyaan

Diketahui c2h4= 52,3kj/mol ,cf4=-680kj/mol ,hf=-268,5kj/mol ,f2=0kj/mol ,hitunglah reaksi untuk: c2h4+ 6f2 2cf4+ 4hf

1 Jawaban

  • (2 (CF₄) + 4 (H-F)) - ((C₂H₄) + 6(F₂))
    = (2 (-680) + 4(-268)) - (52.3) + 6(0)
    = (-1364 + -1027) - 52.3
    = -2436 - 52.3
    = -2488.3

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